Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Two long current carrying conductors are placed parallel to each other at a distance of 8 cm between them. The magnitude of magnetic field produced at mid-point between the two conductors due to current flowing in them is 300 $$\mu$$T. The equal current flowing in the two conductors is:
Two long parallel conductors are 8 cm apart. The magnetic field at the midpoint is 300 $$\mu$$T. Find the equal current and direction.
The midpoint is at 4 cm = 0.04 m from each conductor.
Magnetic field due to each conductor at the midpoint:
$$B = \frac{\mu_0 I}{2\pi d} = \frac{4\pi \times 10^{-7} \times I}{2\pi \times 0.04} = \frac{2 \times 10^{-7} \times I}{0.04} = 5 \times 10^{-6} I \text{ T}$$
If currents are in the same direction: At the midpoint, the fields due to the two wires point in opposite directions (by right-hand rule). The net field = 0. This contradicts 300 $$\mu$$T.
If currents are in opposite directions: At the midpoint, the fields add up:
$$B_{\text{net}} = 2B = 2 \times 5 \times 10^{-6} I = 10^{-5} I$$
$$300 \times 10^{-6} = 10^{-5} I$$
$$I = \frac{300 \times 10^{-6}}{10^{-5}} = 30 \text{ A}$$
Hence, the correct answer is Option C: 30 A in the opposite direction.
Create a FREE account and get:
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.