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In series LCR circuit, the capacitance is changed from $$C$$ to $$4C$$. To keep the resonance frequency unchanged, the new inductance should be :
Resonance: f = 1/(2π√(LC)). For same f with 4C: L_new = L/4. Reduction = L - L/4 = 3L/4.
The correct answer is Option 3: reduced by 3L/4.
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