A wire X of length 50 cm carrying, a current of 2 A is placed parallel to a long wire Y of length 5 m. Wire Y carries a current of 3 A. The distance between the two wires is 5 cm and the currents flow in the same direction. The force acting on wire Y is:

The magnetic force between two parallel current-carrying wires is calculated using the formula derived from Ampere's Force Law:

$$F = \frac{\mu_0 I_1 I_2 L}{2\pi d}$$

$$F = \frac{4\pi \times 10^{-7} \times 2 \times 3 \times 0.5}{2\pi \times 0.05}$$

$$F = \frac{6 \times 10^{-7}}{5 \times 10^{-2}} = 1.2 \times 10^{-5}\text{ N}$$

According to the magnetic force law for parallel conductors, currents flowing in the same direction produce an attractive force. Therefore, wire $$Y$$ is pulled towards wire $$X$$.