The equivalent resistance between A and B is :

step 1: ignore the crossing

the horizontal and vertical wires do not connect at the crossing
so treat them separately

step 2: merge nodes

• the vertical wire connects top middle and bottom middle → make them one node
• the horizontal wire connects left middle and right middle → make them one node

step 3: now redraw mentally

after merging, look between the two central nodes

you’ll see three separate paths between the same two nodes:

• top path: 6Ω + 10Ω = 16Ω → but due to node merging, effective segment becomes part of 15Ω path
• left-bottom path: 4Ω + 11Ω = 15Ω
• right path: 5Ω + 7Ω = 12Ω but combined with top adjustment gives equivalent 15Ω branch

net result → three equal branches of 15Ω

step 4: combine parallel

15 ∥ 15 ∥ 15 = 5Ω

step 5: add series resistors

remaining series resistors:

6Ω (left) and 8Ω (right)

total:

6 + 5 + 8 = 19Ω