In a coil, the current changes from $$-2 \text{ A}$$ to $$+2 \text{ A}$$ in $$0.2 \text{ s}$$ and induces an emf of $$0.1 \text{ V}$$. The self inductance of the coil is :

$$|\varepsilon| = L|dI/dt|$$. $$dI = 2-(-2) = 4$$ A, $$dt = 0.2$$ s.

$$0.1 = L×4/0.2 = 20L$$. $$L = 0.005$$ H = 5 mH.

The correct answer is Option (3): 5 mH.

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