Harish divides two sums of money among his four sons Naresh, Vipin, Bhupesh, and Yogesh. The first sum is divided in the ratio 4 : 3 : 2 : 1 and second in the ratio 5 : 6 : 7 : 8. If the second sum is twice the first, then the largest total is received by

As it is given second sum is twice the first sum.
Let the first total sum be X and second total sum be 2X.

First Distribution :  4 : 3 : 2 : 1
So, Naresh = 4X/10 = 0.4(X)
      Vipin = 3X/10 = 0.3(X)
      Bhupesh = 2X/10 = 0.2(X)
      Yogesh = X/10 = 0.1(X)

Second Distribution :  5 : 6 : 7 : 8.
So, Naresh = 5(2X)/26 =  0.38 (X)
     Vipin = 6(2X)/26 = 0.46(X)
     Bhupesh = 7(2X)/26 = 0.53(X)
     Yogesh = 8(2X)/26 = 0.61(X)

Therefore total distributions for each : 
Naresh = X(0.4+0.38) = 0.78(X)
Vipin = X(0.46+0.3) = 0.76(X)
Bhupesh = X (0.53+0.2) = 0.73(X)
Yogesh = X(0.61+0.1) = 0.71(X)

Therefore, the highest distribution is of Naresh.