The number of electrons flowing per second in the filament of a $$110 \text{ W}$$ bulb operating at $$220 \text{ V}$$ is : (Given $$e = 1.6 \times 10^{-19} \text{ C}$$)

A

$$6.25 \times 10^{17}$$

B

$$1.25 \times 10^{19}$$

C

$$6.25 \times 10^{18}$$

D

$$31.25 \times 10^{17}$$