Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
An electric field is given by $$\left(6\hat{i} + 5\hat{j} + 3\hat{k}\right)$$ N C$$^{-1}$$. The electric flux through a surface area $$30\hat{i}$$ m$$^2$$ lying in YZ-plane (in SI unit) is:
Electric flux is
$$⃗\phi=\vec{E}\cdot\vec{A}$$
Given
$$E=\left(6i+5j^+3k\right)$$
Surface lies in YZ-plane, so area vector is along x-axis:
$$A⃗=30i$$
Therefore,
Dot product would be $$=\ 6\times\ 30$$
=180
Create a FREE account and get:
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.