The maximum potential energy of a block executing simple harmonic motion is 25 J. A is amplitude of oscillation. At $$\dfrac{A}{2}$$, the kinetic energy of the block is

The maximum potential energy of a block in SHM equals the total energy:

$$ E = \frac{1}{2}kA^2 = 25 \text{ J} $$

At displacement $$x = \frac{A}{2}$$:

Potential energy at $$\frac{A}{2}$$:

$$ PE = \frac{1}{2}k\left(\frac{A}{2}\right)^2 = \frac{1}{4} \times \frac{1}{2}kA^2 = \frac{25}{4} = 6.25 \text{ J} $$

Kinetic energy at $$\frac{A}{2}$$:

$$ KE = E - PE = 25 - 6.25 = 18.75 \text{ J} $$

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