Solution
$$\sqrt{15\times\dfrac{163}{5}-89}=\sqrt{3\times163-89}=\sqrt{489-89}=\sqrt{400}=20$$. Thus, (A) - (II)
$$\sqrt{15^2+11\times3^2}=\sqrt{225+99}=\sqrt{324}=18$$. Thus, (B) - (IV)
$$\sqrt{8^2\times7\times5^2-175}=\sqrt{11200-175}=\sqrt{11025}=105$$. Thus, (C) - (I)
$$\sqrt{91+\sqrt{70+\sqrt{121}}}=\sqrt{91+\sqrt{70+11}}=\sqrt{91+9}=10$$. Thus, (D) - (III)
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