Question 10

Let $$f(x) = \left\{\begin{array}{l l}\frac{ax^{2}2ax+3}{4x^{2}+4x-3} ,& x\neq\quad -\frac{3}{2},\frac{1}{2}\\b, & \quad x=-\frac{3}{2},\frac{1}{2}\\\end{array}\right.$$

be continuous at $$x=-\frac{3}{2}$$. If $$f_{0}f(x)=-\frac{7}{5}$$ then x is equal to:

Create a FREE account and get:

  • Free JEE Mains Previous Papers PDF
  • Take JEE Mains paper tests