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The equation of state of a real gas is given by $$\left(P + \frac{a}{V^2}\right)(V - b) = RT$$, where $$P$$, $$V$$ and $$T$$ are pressure, volume and temperature respectively and $$R$$ is the universal gas constant. The dimensions of $$\frac{a}{b^2}$$ is similar to that of :
In the Van der Waals equation: $$\left(P + \frac{a}{V^2}\right)(V - b) = RT$$
$$\frac{a}{V^2}$$ has the same dimensions as $$P$$, so $$[a] = [PV^2]$$.
$$[b] = [V]$$.
$$\frac{a}{b^2} = \frac{PV^2}{V^2} = P$$
The dimensions of $$\frac{a}{b^2}$$ are the same as that of $$P$$.
The answer corresponds to Option (2).
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