NTA JEE Mains 28th Jan 2025 Shift 2

Instructions

For the following questions answer them individually

NTA JEE Mains 28th Jan 2025 Shift 2 - Question 51


Concentrated nitric acid is labelled as 75% by mass. The volume in mL of the solution which contains 30 g of nitric acid is ____. Given : Density of nitric acid solution is 1.25 g/mL .

NTA JEE Mains 28th Jan 2025 Shift 2 - Question 52


Given below are two statements : Statement (I) :

page7_img3

are isomeric compounds. Statement (II) :

page7_img4


are functional group isomers.

NTA JEE Mains 28th Jan 2025 Shift 2 - Question 53


Identify product [A],[B] and [C] in the following reaction sequence.
$$\mathrm{CH_3 - C \equiv CH \xrightarrow[\mathrm{H_2}]{\mathrm{Pd/C}} [A] \xrightarrow[\mathrm{(ii)\ Zn,\ H_2O}]{\mathrm{(i)\ O_3}} [B] + [C]}$$

NTA JEE Mains 28th Jan 2025 Shift 2 - Question 54


The total number of compounds from below when treated with hot $$KMnO_{4}$$ giving benzoic acid is :

page8_img6

NTA JEE Mains 28th Jan 2025 Shift 2 - Question 55


Match List - I with List - II.

page8_img7

Choose the correct answer from the options given below :

NTA JEE Mains 28th Jan 2025 Shift 2 - Question 56


Identify correct statements : (A) Primary amines do not give diazonium salts when treated with $$NaNO_{2}$$ in acidic condition. (B) Aliphatic and aromatic primary amines on heating with $$CHCl_{3}$$and ethanolic KOH form carbylamines. (C) Secondary and tertiary amines also give carbylamine test. (D) Benzenesulfonyl chloride is known as Hinsberg's reagent. (E) Tertiary amines reacts with benzenesulfonyl chloride very easily. Choose the correct answer from the options given below :

NTA JEE Mains 28th Jan 2025 Shift 2 - Question 57


For bacterial growth in a cell culture, growth law is very similar to the law of radioactive decay. Which of the following graphs is most suitable to represent bacterial colony growth ? Where N - Number of Bacteria at any time, $$N_{0}$$ - Initial number of Bacteria.

NTA JEE Mains 28th Jan 2025 Shift 2 - Question 58


The amphoteric oxide among $$V_{2}O_{3}$$ and $$V_{2}O_{5}$$ , upon reaction with alkali leads to formation of an oxide anion. The oxidation state of V in the oxide anion is :

NTA JEE Mains 28th Jan 2025 Shift 2 - Question 59


Arrange the following in increasing order of solubility product :$$\mathrm{Ca(OH)_2, \ AgBr, \ PbS, \ HgS}$$

NTA JEE Mains 28th Jan 2025 Shift 2 - Question 60


The purification method based on the following physical transformation is :

page9_img5
banner

banner
cracku

Boost your Prep!

Download App