NTA JEE Main 25th February 2021 Shift 2

An electron with kinetic energy $$K_1$$ enters between parallel plates of a capacitor at an angle $$\alpha$$ with the plates. It leaves the plates at angle $$\beta$$ with kinetic energy $$K_2$$. Then the ratio of kinetic energies $$K_1 : K_2$$ will be:

Match List I with List II.

An L.C.R. circuit contains resistance of 110 $$\Omega$$ and a supply of 220 V at 300 rad s$$^{-1}$$ angular frequency. If only capacitance is removed from the circuit, current lags behind the voltage by 45°. If on the other hand, only the inductor is removed the current leads by 45° with the applied voltage. The R.M.S. current flowing in the circuit will be:

Consider the diffraction pattern obtained from the sunlight incident on a pinhole of diameter 0.1 $$\mu$$m. If the diameter of the pinhole is slightly increased, it will affect the diffraction pattern such that

An electron of mass $$m_e$$ and a proton of mass $$m_p = 1836 m_e$$ are moving with the same speed. The ratio of their de Broglie wavelength $$\frac{\lambda_{electron}}{\lambda_{proton}}$$ will be:

The stopping potential for electrons emitted from a photosensitive surface illuminated by light of wavelength 491 nm is 0.710 V. When the incident wavelength is changed to a new value, the stopping potential is 1.43 V. The new wavelength is:

The wavelength of the photon emitted by a hydrogen atom when an electron makes a transition from $$n = 2$$ to $$n = 1$$ state is:

The truth table for the following logic circuit is:

For extrinsic semiconductors; when doping level is increased;

If a message signal of frequency $$f_m$$ is amplitude modulated with a carrier signal of frequency $$f_c$$ and radiated through an antenna, the wavelength of the corresponding signal in air is