[Download PDF] IBPS Clerk 14-Dec-2013 Paper with Solutions

Instructions

For the following questions answer them individually

Question 131

The perimeter of a rectangle whose length is 6 metre more than its breadth is 84 metre. What is the area of the triangle whose base is equal to the diagonal of the rectangle and height is equal to the length of the rectangle ?

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Solution

Question 132

Due to decrease of 10% in the price of tea per kg, a consumer buys 250gm of tea more than before for Rs. 270. What is the original price of tea ?

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Solution

Instructions

What will come in place of the question mark (?) in the following questions ?

Question 133

$$(34.5\times14\times42)\div2.8 = ?$$

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Solution

Question 134

-676.76 + 1237.87 + 897.34 - ? = 1294.25

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Solution

Question 135

$$\frac{3}{8}$$ of $$(4624 \div (564-428))=?$$

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Solution

Question 136

$$4\frac{1}{2}+(1\div 2 \frac{8}{9})-3\frac{1}{13}=?$$

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Solution

Question 137

$$(216)^{4} \div (36)^{4} \times6^{5} = (6)^{?}$$

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Solution

Question 138

$$456 \div 24 \times 38 - 958 + 364 = ?$$

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Solution

Question 139

$$3\frac{6}{17}\div 2\frac{7}{34}-1\frac{9}{25}=(?)^2$$

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Solution

Question 140

$$(973 \div 14) \div 5 \times 11 = ?$$

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Solution

BANKING Content

IBPS Clerk 14-Dec-2013

The perimeter of a rectangle whose length is 6 metre more than its breadth is 84 metre. What is the area of the triangle whose base is equal to the diagonal of the rectangle and height is equal to the length of the rectangle ?

Due to decrease of 10% in the price of tea per kg, a consumer buys 250gm of tea more than before for Rs. 270. What is the original price of tea ?

$$(34.5\times14\times42)\div2.8 = ?$$

-676.76 + 1237.87 + 897.34 - ? = 1294.25

$$\frac{3}{8}$$ of $$(4624 \div (564-428))=?$$

$$4\frac{1}{2}+(1\div 2 \frac{8}{9})-3\frac{1}{13}=?$$

$$(216)^{4} \div (36)^{4} \times6^{5} = (6)^{?}$$

$$456 \div 24 \times 38 - 958 + 364 = ?$$

$$3\frac{6}{17}\div 2\frac{7}{34}-1\frac{9}{25}=(?)^2$$

$$(973 \div 14) \div 5 \times 11 = ?$$

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