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$$\left( \frac{4}{7} \right)$$ of a pole is in the mud. When $$\left( \frac{1}{3} \right)$$ of it is pulled out, 250 cm of the pole is still in the mud. The length of the pole is
If the total length of pole = l
The initial part which is in mud = $$\dfrac{\ 4}{7}\left(l\right)$$
As it is said that $$\dfrac{\ 1}{3}$$rd part is pulled out of mud, hence the remaining part which lies inside mud = $$(l)\left(\dfrac{\ 4}{7}-\ \dfrac{\ 1}{3}\right)\ =\ \dfrac{\ 5l}{21}$$
Therefore, $$\dfrac{\ 5l}{21}$$ = 250 cm
Therefore, the value of L = 1050 cm
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