In this question, four numbers are given. Out of these, three are alike in a certain way and one is different. Choose the one which is different from the rest three.

Let's calculate the sum of digits of each number.

Option A: 5+6+9+8 = 28

Option B: 7+8+9+4 = 28

Option C: 8+7+9+3 = 27

Option D: 9+8+6+5 = 28

We can see all the options except option C has sum of digits as 28.

So, option C is the odd one out.

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