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11 when divided by 9 remainder is 2
1011 when divided by 9 remainder is 3
Now, $$11≡2\ mod(9)$$
so, $$11^{1011}≡2^{1011\ }mod(9)$$ ----->(1)
Now $$2^{1011}=\left(2^3\right)^{337}=8^{337}$$
Also, $$8≡-1mod(9)$$
So, $$8^{337}≡-1mod(9)$$
So, we can say $$2^{1011}≡8^{337}mod(9)≡-1\ mod(9)$$
So, $$11^{1011}≡-1\ mod(9)$$ (From (1))
Now, $$-1$$ is a negative remainder, so positive remainder will be 8 --------->(2)
Similarly, $$1011≡3\ mod(9)$$
So, $$1011^{11}≡3^{11\ }mod(9)$$
Now, $$3^{11}=3^2\cdot3^9=9\cdot3^9$$ ,so it is definitely divisible by 9
So, in this part remainder will be $$0$$ --------->(3)
From (2) and (3) we can say, remainder=$$8+0=8$$
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