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The population of a village is 5000. If in a year, the number of males were to increase by 5% and that of females by 3% annually, the population would grow to 5202 at the end of the year. If M is the number of males and F is the number of females in the village, then (M,F) =
Let the number of males be x and the number of females be y.
$$x+y=5000\rightarrow1$$
If the number of males were to increase by 5% and that of females by 3% annually, the population would grow to 5202 at the end of the year.
$$1.05x+1.03y=5202\rightarrow2$$
Multiply eq. 1 by 1.05, and subtract eq. 2 from it-
$$1.05y-1.03y=5000(1.05)-5202$$
$$0.02y=48$$
$$y=2400$$
Thus, $$x=2600$$
Therefore, the number of males is 2600, and the number of females is 2400.
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