Question 30

The set of values of x which satisfy the inequality $$0.7^{2x^{2}-3x+4} < 0.343$$ is

Solution

Given,

$$0.7^{2x^{2}-3x+4} < 0.343$$

or, $$0.7^{2x^2-3x+4}<0.7^3$$

since $$0.7$$ is a fractional value so, $$2x^2-3x+4>3$$

or, $$2x^2-3x+1>0$$

or, $$2x^2-2x-x+1>0$$

or, $$(2x-1)(x-1)>0$$

or, $$x<\dfrac{1}{2}$$ and $$x>1$$

So, option D is the correct answer.

View More Questions From Temporary

Create a FREE account and get: