Question 3

At what angle the hands of a clock are inclined at 15 minutes past 5?

Solution

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Angle between hands of a clock at H:M  = $$|\dfrac{\ 11}{2}M-30H|$$ degrees.

So, at 5:15 pm ,the angle = $$|\frac{\ 11}{2}\left(15\right)-30\left(5\right)|\ =\left|-67.5\right|\ =\ 67.5\ $$

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