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Question 28

The factors of polynomial $$x^{3}-6x^{2}+11x-6$$ are:

$$x=1$$ will make the polynomial $$x^{3}-6x^{2}+11x-6=0$$. Thus, $$x-1$$ is a factor of the given polynomial, so we will divide the given polynomial by this factor. Thus, we will get 

$$x^{3}-6x^{2}+11x-6=(x-1)(x^2-5x+6)$$

$$x^{3}-6x^{2}+11x-6=(x-1)(x-2)(x-3)$$

Thus, the factors of the given polynomial are $$x-1$$, $$x-2$$, and $$x-3$$. 

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