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Given $$f(x) = x^2 + \log_{3} x$$ and $$g(y) = 2y + f(y)$$, the value of g(3) equals
$$g(y) = 2y + f(y)$$
$$g(y) = 2y + y^2 + \log_{3}y$$
$$g(3) = 2(3) + 3^2 + \log_{3}3$$
$$g(3) = 6 + 9 + 1$$
$$g(3) = 16$$
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