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In a class, 25% of all students read news from the Internet. Moreover, 45% of all students read news from printed newspaper. Further, 20% of all students read news from both the Internet and printed newspaper and they do not play video games. It is also known that 30% of the students who do not read news play video games. The minimum percentage of students who do not play video games is
Let total = 100. Internet readers = 25, Print readers = 45, both = 20 (and these 20 do not play games). Either reads news = $$25 + 45 - 20 = 50$$. So non-readers = 50.
Among non-readers, 30% play games → 15 play, 35 don't.
Minimum who do not play games = $$20$$ (both readers, given) + $$35$$ (non-readers who don't play) = $$55$$. Internet-only (5) and Print-only (25) are unknown, so the minimum is 55%.
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