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Educational materials for IPMAT and IIMB UG preparation
If $$\log_{5}\log_{8}(x^2 - 1) = 0$$, then a possible value of x is
$$\log_{5}\log_{8}(x^2 - 1) = 0$$
$$\log_{8}(x^2 - 1) = 1$$
$$(x^2 - 1) = 8$$
$$x^2=9$$
$$x=3\ or\ x=-3$$
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