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Fruits were purchased for Rs 350. 9 boys ate $$\dfrac{3}{5}th$$ of them in 2 hours. 6 boys feel their stomach as full so do not eat further. In how many hours the remaining fruits will get finished by remaining boys?
It is given 9 boys ate $$\dfrac{3}{5}th$$ of them in 2 hours.
or, 9 boys ate $$\dfrac{3}{10}th$$ of them in 1 hour.
or, 1 boy ate $$\dfrac{3}{10\times\ 9}=\dfrac{1}{30}th$$ of them in 1 hour.
Now, $$\dfrac{3}{5}th$$ of fruits have been eaten
So, amount of fruits remaining are $$\dfrac{2}{5}th$$.
Also, number of persons that will eat the remaining fruits = $$9-6=3$$
So, required time to eat = $$\dfrac{\dfrac{2}{5}}{\dfrac{1}{30}\times\ 3}=\dfrac{\dfrac{2}{5}}{\dfrac{1}{10}}=\dfrac{2}{5}\times\ 10=4$$ hours
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