Question 11
Two poles of height 6 m and 11 m stand vertically upright on a plane ground. If the distance between their foot is 12 m, then the distance between their tops is
Solution
We can see that AB = 5m, and BC = 12m
We need to find the distance between the top of the two poles, which is equal to AC.
$$AC^2=AB^2+BC^2$$
$$AC^2=5^2+12^2$$
$$AC^2=169$$
$$AC=13\ m$$
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