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What will be the least number which when divided by 12, 21 and 35 leaves 6 as a remainder in each case?
To find the least number which when divided by 12, 21 and 35 leaves 6 as a remainder in each case, we have to find the LCM of 12, 21 and 35 and add 6 in that value, as that is the remainder.
$$N=LCM(12,21,35)+6$$
$$N=420+6$$
$$N=426$$