Sign in
Please select an account to continue using cracku.in
↓ →
The length of canvas 1.1 m wide required to build a conical tent of height 14m and the floor area 346.5 $$m^{2}$$ is.
It is given conical base area = 346.5
So, $$\pi\left(r\right)^2\ $$ = 346.5
This gives radius = 10.5
Slant length of cone = $$\sqrt{h^2+r^2\ }$$
= $$\sqrt{14^2+10.5^2\ }\ =\ 17.5$$
Surface area of cone = $$\pi\ rl$$ = (10.5)(17.5)(3.14) = 576.97
Therefore, the length of canvas = 576.97/1.1 = 524.52
Crack IPMAT 2026 with Cracku
Educational materials for IPMAT and IIMB UG preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.