If f(1) = 1 and f(n) = 3n - f(n - 1) for all integers n > 1 , then the value of f(2023) is _________

Let's understand the pattern here.

F(1) = 1

F(2) = 3*2 - 1

F(3) = 3*3 - 3*2 + 1 = 3*(3-2)+1

F(4) = 3*4 - 3*3 + 3*2 - 1 = 3*(4-3)+3*2+1

F(5) = 3*5 - 3*4 + 3*3 - 3*2 + 1 = 3(5-4)+3(3-2)+1 = $$3\cdot\frac{\left(5-1\right)}{2}+1$$

For odd numbers, this can be interpreted as F(n) = $$3\cdot\frac{\left(n-1\right)}{2}+1$$

For F(2023) =  $$3\cdot\frac{\left(2023-1\right)}{2}+1$$ = $$3\cdot\frac{2022}{2}+1=3\cdot1011+1\ =3034$$