SBI PO 2000

Instructions

Find the what approximate value which should be come in place of the following questions .(You are not expected to  calculate exact value).

SBI PO 2000 - Question 141


$$(10008.99)^{2}/(10009.001)\times\sqrt{3589}\times0.4987=?$$

Video Solution

SBI PO 2000 - Question 142


$$\sqrt{45689}=?$$

Video Solution
Instructions

In each of the following questions a number series is given.After the series , a number is given followed by a (a),(b),(c),(d) and (e).You are required to complete the series starting with the number given following the sequences of the given series?

SBI PO 2000 - Question 143


2     6    40  1636  2676504
1   (a)   (b)   (c)        (d)          (e)
What will come in place of (d) ?

Video Solution

SBI PO 2000 - Question 144


3    7      24    101   512
5   (a)   (b)     (c)     (d)   (e)
What will come in place of (c) ?

Video Solution

SBI PO 2000 - Question 145


3     9      81    6561
2    (a)    (b)      (c)      (d)    (e)
What will come in place of (d) ?

Video Solution

SBI PO 2000 - Question 146


150   299    601  1197 2401   4793
60     (a)    ( b)     (c)    (d)      (e)
What will come in place of (e) ?

Video Solution

SBI PO 2000 - Question 147


12  24  96  576  4608
5   (a)  (b)  (c)     (d)       (e)
What will come in place of (c) ?

Video Solution
Instructions

For the following questions answer them individually

SBI PO 2000 - Question 148


A number gets reduced to its one third when 48 is subtracted from it.What is two third of that Number?

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SBI PO 2000 - Question 149


What will be the the compound interest acquired on sum of Rs 12,000/- for 3 years at the rate of 10 % per annum ?

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SBI PO 2000 - Question 150


Jayesh is twice as old as Vijay and half as old as Suresh .If sum of Suresh’s and Vijay’s age is 85 years what is the Jayesh’s age in years?

Video Solution
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