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NTA JEE Mains 29th Jan 2024 Shift 1 - Mathematics

For the following questions answer them individually

Let $$(5, \frac{a}{4})$$, be the circumcenter of a triangle with vertices $$A(a, -2)$$, $$B(a, 6)$$ and $$C(\frac{a}{4}, -2)$$. Let $$\alpha$$ denote the circumradius, $$\beta$$ denote the area and $$\gamma$$ denote the perimeter of the triangle. Then $$\alpha + \beta + \gamma$$ is

In a $$\Delta ABC$$, suppose $$y = x$$ is the equation of the bisector of the angle $$B$$ and the equation of the side $$AC$$ is $$2x - y = 2$$. If $$2AB = BC$$ and the point $$A$$ and $$B$$ are respectively $$(4, 6)$$ and $$(\alpha, \beta)$$, then $$\alpha + 2\beta$$ is equal to

Let $$R$$ be a relation on $$Z \times Z$$ defined by $$(a, b)R(c, d)$$ if and only if $$ad - bc$$ is divisible by $$5$$. Then $$R$$ is

If $$f(x) = \begin{cases} 2 + 2x, & -1 \leq x < 0 \\ 1 - \frac{x}{3}, & 0 \leq x \leq 3 \end{cases}$$; $$g(x) = \begin{cases} -x, & -3 \leq x \leq 0 \\ x, & 0 < x \leq 1 \end{cases}$$, then range of $$(f \circ g(x))$$ is

Consider the function $$f : [\frac{1}{2}, 1] \to R$$ defined by $$f(x) = 4\sqrt{2}x^3 - 3\sqrt{2}x - 1$$. Consider the statements
(I) The curve $$y = f(x)$$ intersects the $$x$$-axis exactly at one point
(II) The curve $$y = f(x)$$ intersects the $$x$$-axis at $$x = \cos\frac{\pi}{12}$$
Then

If the value of the integral $$\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \left(\frac{x^2 \cos x}{1 + \pi^x} + \frac{1 + \sin^2 x}{1 + e^{(\sin x)^{2023}}}\right) dx = \frac{\pi}{4}(\pi + a) - 2$$, then the value of $$a$$ is

For $$x \in (-\frac{\pi}{2}, \frac{\pi}{2})$$, if $$y(x) = \int \frac{\csc x + \sin x}{\csc x \sec x + \tan x \sin^2 x} dx$$ and $$\lim_{x \to (\frac{\pi}{2})^-} y(x) = 0$$ then $$y(\frac{\pi}{4})$$ is equal to

Let $$\vec{a}, \vec{b}$$ and $$\vec{c}$$ be three non-zero vectors such that $$\vec{b}$$ and $$\vec{c}$$ are non-collinear. If $$\vec{a} + 5\vec{b}$$ is collinear with $$\vec{c}$$, $$\vec{b} + 6\vec{c}$$ is collinear with $$\vec{a}$$ and $$\vec{a} + \alpha\vec{b} + \beta\vec{c} = \vec{0}$$, then $$\alpha + \beta$$ is equal to

Let $$O$$ be the origin and the position vector of $$A$$ and $$B$$ be $$2\hat{i} + 2\hat{j} + \hat{k}$$ and $$2\hat{i} + 4\hat{j} + 4\hat{k}$$ respectively. If the internal bisector of $$\angle AOB$$ meets the line $$AB$$ at $$C$$, then the length of $$OC$$ is

Let $$PQR$$ be a triangle with $$R(-1, 4, 2)$$. Suppose $$M(2, 1, 2)$$ is the mid point of $$PQ$$. The distance of the centroid of $$\Delta PQR$$ from the point of intersection of the line $$\frac{x-2}{0} = \frac{y}{2} = \frac{z+3}{-1}$$ and $$\frac{x-1}{1} = \frac{y+3}{-3} = \frac{z+1}{1}$$ is

Equations of two diameters of a circle are $$2x - 3y = 5$$ and $$3x - 4y = 7$$. The line joining the points $$(-\frac{22}{7}, -4)$$ and $$(-\frac{1}{7}, 3)$$ intersects the circle at only one point $$P(\alpha, \beta)$$. Then $$17\beta - \alpha$$ is equal to _______

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If the points of intersection of two distinct conics $$x^2 + y^2 = 4b$$ and $$\frac{x^2}{16} + \frac{y^2}{b^2} = 1$$ lie on the curve $$y^2 = 3x^2$$, then $$3\sqrt{3}$$ times the area of the rectangle formed by the intersection points is _______.

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The area (in sq. units) of the part of circle $$x^2 + y^2 = 169$$ which is below the line $$5x - y = 13$$ is $$\frac{\pi\alpha}{2\beta} - \frac{65}{2} + \frac{\alpha}{\beta}\sin^{-1}(\frac{12}{13})$$ where $$\alpha, \beta$$ are coprime numbers. Then $$\alpha + \beta$$ is equal to _______

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If the solution curve $$y = y(x)$$ of the differential equation $$(1 + y^2)(1 + \log_e x)dx + xdy = 0$$, $$x > 0$$ passes through the point $$(1, 1)$$ and $$y(e) = \frac{\alpha - \tan(\frac{3}{2})}{\beta + \tan(\frac{3}{2})}$$, then $$\alpha + 2\beta$$ is _______

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