NTA JEE Main 9th January 2019 Shift 1

Instructions

For the following questions answer them individually

NTA JEE Main 9th January 2019 Shift 1 - Question 41


Arrange the following amines in the decreasing order of basicity.

NTA JEE Main 9th January 2019 Shift 1 - Question 42


Which amongst the following is the strongest acid?

NTA JEE Main 9th January 2019 Shift 1 - Question 43


The compounds A and B in the following reaction are, respectively:

NTA JEE Main 9th January 2019 Shift 1 - Question 44


A water sample has ppm level concentration of the following metals: Fe = 0.2; Mn = 5.0; Cu = 3.0; Zn = 5.0. The metal that makes the water sample unsuitable for drinking is:

NTA JEE Main 9th January 2019 Shift 1 - Question 45


The one that is extensively used as a piezoelectric material is:

NTA JEE Main 9th January 2019 Shift 1 - Question 46


A solution of sodium sulphate contains 92 g of Na$$^+$$ ions per kilogram of water. The molality of Na$$^+$$ ions in that solution in mol kg$$^{-1}$$ is:

NTA JEE Main 9th January 2019 Shift 1 - Question 47


Which one of the following statements regarding Henry's law is not correct?

NTA JEE Main 9th January 2019 Shift 1 - Question 48


The anodic half-cell of lead-acid battery is recharged using electricity of 0.05 Faraday. The amount of $$PbSO_4$$ electrolyzed in g during the process is: (Molar mass of $$PbSO_4 = 303$$ g mol$$^{-1}$$)

NTA JEE Main 9th January 2019 Shift 1 - Question 49


The following results were obtained during kinetic studies of the reaction.
$$2A + B \rightarrow$$ product

Experiment I: A = 0.10 mol L$$^{-1}$$, B = 0.20 mol L$$^{-1}$$, Rate = $$6.93 \times 10^{-3}$$ mol L$$^{-1}$$ min$$^{-1}$$
Experiment II: A = 0.10 mol L$$^{-1}$$, B = 0.25 mol L$$^{-1}$$, Rate = $$6.93 \times 10^{-3}$$ mol L$$^{-1}$$ min$$^{-1}$$
Experiment III: A = 0.20 mol L$$^{-1}$$, B = 0.30 mol L$$^{-1}$$, Rate = $$1.386 \times 10^{-2}$$ mol L$$^{-1}$$ min$$^{-1}$$

The time (in minutes) required to consume half of A is:

NTA JEE Main 9th January 2019 Shift 1 - Question 50


Adsorption of a gas follows Freundlich adsorption isotherm. In the given plot, $$x$$ is the mass of the gas adsorbed on mass $$m$$ of the adsorbent at pressure P. $$\frac{x}{m}$$ is proportional to:

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