NTA JEE Main 9th April 2017 Online

Instructions

For the following questions answer them individually

NTA JEE Main 9th April 2017 Online - Question 71


The eccentricity of an ellipse having centre at the origin, axes along the co-ordinate axes and passing through the points $$(4, -1)$$ and $$(-2, 2)$$ is

NTA JEE Main 9th April 2017 Online - Question 72


The contrapositive of the statement 'If two numbers are not equal, then their squares are not equal', is

NTA JEE Main 9th April 2017 Online - Question 73


The sum of 100 observations and the sum of their squares are 400 & 2475, respectively. Later on, three observations 3, 4 & 5 were found to be incorrect. If the incorrect observations are omitted, then the variance of the remaining observations is

NTA JEE Main 9th April 2017 Online - Question 74


For two $$3 \times 3$$ matrices $$A$$ and $$B$$, let $$A + B = 2B'$$ and $$3A + 2B = I_3$$, where $$B'$$ is the transpose of $$B$$ and $$I_3$$ is $$3 \times 3$$ identity matrix. Then:

NTA JEE Main 9th April 2017 Online - Question 75


If $$x = a$$, $$y = b$$, $$z = c$$ is a solution of the system of linear equations
$$x + 8y + 7z = 0$$
$$9x + 2y + 3z = 0$$
$$x + y + z = 0$$
Such that the point $$(a, b, c)$$ lies on the plane $$x + 2y + z = 6$$, then $$2a + b + c$$ equals:

NTA JEE Main 9th April 2017 Online - Question 76


A value of $$x$$ satisfying the equation $$\sin\left[\cot^{-1}(1 + x)\right] = \cos\left[\tan^{-1}x\right]$$, is:

NTA JEE Main 9th April 2017 Online - Question 77


The function $$f : N \to I$$ defined by $$f(x) = x - 5\left[\frac{x}{5}\right]$$, where $$N$$ is the set of natural numbers and $$[x]$$ denotes the greatest integer less than or equal to $$x$$, is:

NTA JEE Main 9th April 2017 Online - Question 78


The value of $$k$$ which the function $$f(x) = \begin{cases} \left(\frac{4}{5}\right)^{\frac{\tan 4x}{\tan 5x}}, & 0 < x < \frac{\pi}{2} \\ k + \frac{2}{5}, & x = \frac{\pi}{2} \end{cases}$$ is continuous at $$x = \frac{\pi}{2}$$, is

NTA JEE Main 9th April 2017 Online - Question 79


If $$2x = y^{\frac{1}{5}} + y^{-\frac{1}{5}}$$ and $$(x^2 - 1)\frac{d^2y}{dx^2} + \lambda x \frac{dy}{dx} + ky = 0$$, then $$\lambda + k$$ is equal to

NTA JEE Main 9th April 2017 Online - Question 80


The function $$f$$ defined by $$f(x) = x^3 - 3x^2 + 5x + 7$$ is:

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