NTA JEE Main 31st January 2023 Shift 1

On complete combustion, 0.492 g of an organic compound gave 0.792 g of CO$$_2$$. The % of carbon in the organic compound is (Nearest integer)

Zinc reacts with hydrochloric acid to give hydrogen and zinc chloride. The volume of hydrogen gas produced at STP from the reaction of 11.5 g of zinc with excess HCl is L (Nearest integer)
(Given: Molar mass of Zn is 65.4 g mol$$^{-1}$$ and Molar volume of H$$_2$$ at STP = 22.7 L)

The enthalpy change for the conversion of $$\dfrac{1}{2}$$Cl$$_2$$(g) to Cl$$^-$$(aq) is (-) ______ kJmol$$^{-1}$$ (Nearest integer)
Given: $$\Delta_{dis}H^0_{Cl_2(g)} = 240$$ kJmol$$^{-1}$$
$$\Delta_{eg}H^o_{Cl(g)} = -350$$ kJmol$$^{-1}$$
$$\Delta_{hyd}H^o_{Cl^-(g)} = -380$$ kJmol$$^{-1}$$

For reaction: $$SO_2(g) + \dfrac{1}{2}O_2(g) \rightleftharpoons SO_3(g)$$ $$K_P = 2 \times 10^{12}$$ at 27°C and 1 atm pressure. The $$K_c$$ for the same reaction is ______ $$\times 10^{13}$$. (Nearest integer)
(Given $$R = 0.082$$ L atm K$$^{-1}$$ mol$$^{-1}$$)

The total pressure of a mixture of non-reacting gases X(0.6 g) and Y(0.45 g) in a vessel is 740 mm of Hg. The partial pressure of the gas X is mm of Hg. (Nearest Integer)
(Given: molar mass X = 20 and Y = 45 g mol$$^{-1}$$)

At 27°C, a solution containing 2.5 g of solute in 250.0 mL of solution exerts an osmotic pressure of 400 Pa. The molar mass of the solute is g mol$$^{-1}$$ (Nearest integer)
(Given: R = 0.083 L bar$$^{-1}$$ mol$$^{-1}$$)

The logarithm of equilibrium constant for the reaction $$Pd^{2+} + 4Cl^- \rightleftharpoons PdCl_4^{2-}$$ is (Nearest integer)
Given: $$\dfrac{2.303RT}{F} = 0.06$$ V
$$Pd^{2+}_{(aq)} + 2e^- \rightleftharpoons Pd(s)$$ $$E^o = 0.83$$ V
$$PdCl_4^{2-}(aq) + 2e^- \rightleftharpoons Pd(s) + 4Cl^-(aq)$$ $$
$$E^o = 0.65$$ V

$$A \rightarrow B$$
The rate constants of the above reaction at 200 K and 300 K are 0.03 min$$^{-1}$$ and 0.05 min$$^{-1}$$ respectively. The activation energy for the reaction is J (Nearest integer)
(Given: ln 10 = 2.3, R = 8.3 J K$$^{-1}$$ mol$$^{-1}$$, log 5 = 0.70, log 3 = 0.48, log 2 = 0.30)

The oxidation state of phosphorus in hypophosphoric acid is

How many of the transformation given below would result in aromatic amines?