NTA JEE Main 26th June 2022 Shift 2

Instructions

For the following questions answer them individually

NTA JEE Main 26th June 2022 Shift 2 - Question 61


If $$A = \sum_{n=1}^{\infty} \frac{1}{(3+(- 1)^n)^n}$$ and $$B = \sum_{n=1}^{\infty} \frac{(-1)^n}{(3+(-1)^n)^n}$$, then $$\frac{A}{B}$$ is equal to

NTA JEE Main 26th June 2022 Shift 2 - Question 62


$$16\sin(20°)\sin(40°)\sin(80°)$$ is equal to

NTA JEE Main 26th June 2022 Shift 2 - Question 63


If $$m$$ is the slope of a common tangent to the curves $$\frac{x^2}{16} + \frac{y^2}{9} = 1$$ and $$x^2 + y^2 = 12$$, then $$12m^2$$ is equal to

NTA JEE Main 26th June 2022 Shift 2 - Question 64


The locus of the mid-point of the line segment joining the point $$(4, 3)$$ and the points on the ellipse $$x^2 + 2y^2 = 4$$ is an ellipse with eccentricity

NTA JEE Main 26th June 2022 Shift 2 - Question 65


The normal to the hyperbola $$\frac{x^2}{a^2} - \frac{y^2}{9} = 1$$ at the point $$(8, 3\sqrt{3})$$ on it passes through the point

NTA JEE Main 26th June 2022 Shift 2 - Question 66


$$\lim_{x \to 0} \frac{\cos(\sin x) - \cos x}{x^4}$$ is equal to

NTA JEE Main 26th June 2022 Shift 2 - Question 67


Let $$r \in (P, q, \sim p, \sim q)$$ be such that the logical statement $$r \vee (\sim p) \Rightarrow (p \wedge q) \vee r$$ is a tautology. Then $$r$$ is equal to

NTA JEE Main 26th June 2022 Shift 2 - Question 68


Let the mean of 50 observations is 15 and the standard deviation is 2. However, one observation was wrongly recorded. The sum of the correct and incorrect observations is 70. If the mean of the correct set of observations is 16, then the variance of the correct set is equal to

NTA JEE Main 26th June 2022 Shift 2 - Question 69


If the system of equations $$\alpha x + y + z = 5, x + 2y + 3z = 4, x + 3y + 5z = \beta$$. Has infinitely many solutions, then the ordered pair $$(\alpha, \beta)$$ is equal to

NTA JEE Main 26th June 2022 Shift 2 - Question 70


If the inverse trigonometric functions take principal values, then
$$\cos^{-1}\left(\frac{3}{10}\cos\left(\tan^{-1}\left(\frac{4}{3}\right)\right) + \frac{2}{5}\sin\left(\tan^{-1}\left(\frac{4}{3}\right)\right)\right)$$ is equal to

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