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NTA JEE Main 25th January 2023 Shift 2 - Mathematics

For the following questions answer them individually

The equations of two sides of a variable triangle are $$x = 0$$ and $$y = 3$$, and its third side is a tangent to the parabola $$y^2 = 6x$$. The locus of its circumcentre is:

Let $$\triangle, \nabla \in \{\wedge, \vee\}$$ be such that $$(p \to q) \triangle (p \nabla q)$$ is a tautology. Then

Let $$A, B, C$$ be $$3 \times 3$$ matrices such that $$A$$ is symmetric and $$B$$ and $$C$$ are skew-symmetric. Consider the statements
(S1) $$A^{13}B^{26} - B^{26}A^{13}$$ is symmetric
(S2) $$A^{26}C^{13} - C^{13}A^{26}$$ is symmetric
Then,

Let $$A = \begin{bmatrix} \frac{1}{\sqrt{10}} & \frac{3}{\sqrt{10}} \\ \frac{-3}{\sqrt{10}} & \frac{1}{\sqrt{10}} \end{bmatrix}$$ and $$B = \begin{bmatrix} 1 & -i \\ 0 & 1 \end{bmatrix}$$, where $$i = \sqrt{-1}$$. If $$M = A^T BA$$, then the inverse of the matrix $$AM^{2023}A^T$$ is

If the function $$f(x) = \begin{cases} (1+|\cos x|)^{\frac{\lambda}{|\cos x|}}, & 0 < x < \frac{\pi}{2} \\ \mu, & x = \frac{\pi}{2} \\ e^{\frac{\cot 6x}{\cot 4x}}, & \frac{\pi}{2} < x < \pi \end{cases}$$ is continuous at $$x = \frac{\pi}{2}$$, then $$9\lambda + 6\log_e \mu + \mu^6 - e^{6\lambda}$$ is equal to

Let the function $$f(x) = 2x^3 + (2p-7)x^2 + 3(2p-9)x - 6$$ have a maxima for some value of $$x < 0$$ and a minima for some value of $$x > 0$$. Then, the set of all values of $$p$$ is

Let T and C respectively, be the transverse and conjugate axes of the hyperbola $$16x^2 - y^2 + 64x + 4y + 44 = 0$$. Then the area of the region above the parabola $$x^2 = y + 4$$, below the transverse axis T and on the right of the conjugate axis C is:

If the four points, whose position vectors are $$3\hat{i} - 4\hat{j} + 2\hat{k}$$, $$\hat{i} + 2\hat{j} - \hat{k}$$, $$-2\hat{i} - \hat{j} + 3\hat{k}$$ and $$5\hat{i} - 2\alpha\hat{j} + 4\hat{k}$$ are coplanar, then $$\alpha$$ is equal to

Let $$\vec{a} = -\hat{i} - \hat{j} + \hat{k}$$, $$\vec{a} \cdot \vec{b} = 1$$ and $$\vec{a} \times \vec{b} = \hat{i} - \hat{j}$$. Then $$\vec{a} - 6\vec{b}$$ is equal to

The foot of perpendicular of the point $$(2, 0, 5)$$ on the line $$\frac{x+1}{2} = \frac{y-1}{5} = \frac{z+1}{-1}$$ is $$(\alpha, \beta, \gamma)$$. Then, which of the following is NOT correct?

Suppose Anil's mother wants to give 5 whole fruits to Anil from a basket of 7 red apples, 5 white apples and 8 oranges. If in the selected 5 fruits, at least 2 orange, at least one red apple and at least one white apple must be given, then the number of ways, Anil's mother can offer 5 fruits to Anil is _____.

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For the two positive numbers $$a, b$$, if $$a, b$$ and $$\frac{1}{18}$$ are in a geometric progression, while $$\frac{1}{a}$$, 10 and $$\frac{1}{b}$$ are in an arithmetic progression, then, $$16a + 12b$$ is equal to _____.

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Points $$P(-3, 2)$$, $$Q(9, 10)$$ and $$R(a, 4)$$ lie on a circle $$C$$ with $$PR$$ as its diameter. The tangents to $$C$$ at the points $$Q$$ and $$R$$ intersect at the point $$S$$. If $$S$$ lies on the line $$2x - ky = 1$$, then $$k$$ is equal to _____.

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25% of the population are smokers. A smoker has 27 times more chances to develop lung cancer then a non-smoker. A person is diagnosed with lung cancer and the probability that this person is a smoker is $$\frac{k}{10}$$. Then the value of $$k$$ is _____.

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