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NTA JEE Main 15th April 2018 Shift 2 - Mathematics

For the following questions answer them individually

Let $$A_n = \left(\frac{3}{4}\right) - \left(\frac{3}{4}\right)^2 + \left(\frac{3}{4}\right)^3 - \ldots + (-1)^{n-1}\left(\frac{3}{4}\right)^n$$ and $$B_n = 1 - A_n$$. Then, the least odd natural number p, so that $$B_n > A_n$$, for all $$n \geq p$$ is:

If a, b, c are in A.P. and $$a^2, b^2, c^2$$ are in G.P. such that $$a < b < c$$ and $$a + b + c = \frac{3}{4}$$, then the value of a is:

Consider the following two statements.
Statement p: The value of $$\sin 120^\circ$$ can be divided by taking $$\theta = 240^\circ$$ in the equation $$2\sin\frac{\theta}{2} = \sqrt{1 + \sin\theta} - \sqrt{1 - \sin\theta}$$.
Statement q: The angles A, B, C and D of any quadrilateral ABCD satisfy the equation $$\cos\left(\frac{1}{2}(A+C)\right) + \cos\left(\frac{1}{2}(B+D)\right) = 0$$.
Then the truth values of p and q are respectively:

The sides of a rhombus ABCD are parallel to the lines, $$x - y + 2 = 0$$ and $$7x - y + 3 = 0$$. If the diagonals of the rhombus intersect at P(1, 2) and the vertex A (different from the origin) is on the y axis, then the ordinate of A is:

A normal to the hyperbola, $$4x^2 - 9y^2 = 36$$ meets the co-ordinate axes x and y at A and B, respectively. If the parallelogram OABP (O being the origin) is formed, then the locus of P is:

A tower T$$_1$$ of height 60 m is located exactly opposite to a tower T$$_2$$ of height 80 m on a straight road. From the top of T$$_1$$, if the angle of depression of the foot of T$$_2$$ is twice the angle of elevation of the top of T$$_2$$, then the width (in m) of the road between the feet of the towers T$$_1$$ and T$$_2$$ is:

Let $$f : A \to B$$ be a function defined as $$f(x) = \frac{x-1}{x-2}$$, where $$A = R - \{2\}$$ and $$B = R - \{1\}$$. Then f is:

Let $$f(x)$$ be a polynomial of degree 4 having extreme values at $$x = 1$$ and $$x = 2$$. If $$\lim_{x \to 0}\left(\frac{f(x)}{x^2} + 1\right) = 3$$, then $$f(-1)$$ is equal to:

If the position vectors of the vertices A, B and C of a $$\triangle$$ABC are respectively $$4\hat{i} + 7\hat{j} + 8\hat{k}$$, $$2\hat{i} + 3\hat{j} + 4\hat{k}$$ and $$2\hat{i} + 5\hat{j} + 7\hat{k}$$, then the position vector of the point, where the bisector of $$\angle A$$ meets BC is:

An angle between the lines whose direction cosines are given by the equations, $$l + 3m + 5n = 0$$ and $$5lm - 2mn + 6nl = 0$$, is:

A player X has a biased coin whose probability of showing heads is p and a player Y has a fair coin. They start playing a game with their own coins and play alternately. The player who throws a head first is a winner. If X starts the game, and the probability of winning the game by both the players is equal, then the value of 'p' is: