Time, speed, distance and work problems appear in SSC exams (CGL and CHSL). We have given some of the SSC CHSL time and work questions asked in previous year question papers.

**Time and Work Problems for SSC CHSL:**

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**Question 1:
**

Rakesh goes on a trip on his motor-cycle and rides for 368 kms. If he rides for 5 hours at a speed of 49 km/hr, at what speed he travels for the remaining 3 hours of the journey?

a) 58 km/hr

b) 41 km/hr

c) 54 km/hr

d) 46 km/hr

**Question 2:
**

To cover a distance of 333 km in 2 hours by a car, what should be the average speed of the car (in meter/second)?

a) 166.5

b) 46.25

c) 83.25

d) 92.5

**Question 3:**

A thief is stopped by a policeman from a distance of 150 metres. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief as 7 km/hr and that of policeman as 9 km/hr, how far the thief would have run, before he is over-taken by the policeman?

a) 420 metres

b) 630 metres

c) 315 metres

d) 525 metres

Question 4:

Two cars travel from city A to city B at a speed of 60 and 108 km/hr respectively. If one car takes 2 hours lesser time than the other car for the journey, then the distance between City A and City B?

a) 270 km

b) 324 km

c) 405 km

d) 216 km

**Question 5:**

Two cars travel from city A to city B at a speed of 30 and 45 km/hr respectively. If one car takes 2.5 hours lesser time than the other car for the journey, then the distance between City A and City B is:

a) 270 km

b) 338 km

c) 180 km

d) 225 km

**Question 6:**

To cover a distance of 216 km in 3.2 hours, what should be the average speed of the car in meters/second?

a) 67.5 m/s

b) 33.75 m/s

c) 37.5 m/s

d) 18.75 m/s

**Question 7:**

A mason can build a wall in 70 hours. After 7 hours he takes a break. What fraction of the wall is yet to be built?

a) 0.9

b) 0.8

c) 0.5

d) 0.75

**Solutions: (1 to 7)**

1) Answer (b)

Total distance covered = 368 km

He rides for 5 hours at a speed of 49 km/hr

=> Distance covered = $$5 \times 49 = 245$$ km

Distance left = 368 – 245 = 123 km

$$\therefore$$ Speed he should travel for the remaining 3 hours of the journey = $$\frac{123}{3} = 41$$ km/hr

=> Ans – (B)

**2) Answer (b)**

The car covers 333 km in 2 hours

Speed of car (in km/hr) = $$\frac{333}{2} = 166.5$$ km/hr

=> Speed in m/s = $$166.5 \times \frac{5}{18}$$

= $$5 \times 9.25 = 46.25$$ m/s

$$\therefore$$ In 1 second, it travels 46.25 metres

=> Ans – (B)

**3) Answer (d)**

Since the thief is escaping from the police man, thus they both are running in same direction.

Speed of thief = 7 km/hr and speed of policeman = 9 km/hr

=> Relative speed = 9 – 7 = 2 km/hr

Distance between them = 150 metres = 0.15 km

=> Time taken = $$\frac{distance}{speed}$$

= $$\frac{0.15}{2} = \frac{3}{40}$$ hr

$$\therefore$$ Distance covered by thief before he was caught = $$7 \times \frac{3}{40}$$

= 0.525 km = 525 metres

=> Ans – (D)

**4) Answer (a)**

Let the distance between City A and City B = $$d$$ km

Speed of first car = 60 km/hr and speed of second car = 108 km/hr

Let time taken by first car = $$t$$ hrs and time taken by second car = $$(t – 2)$$ hrs

Using, speed = distance/time for first car :

=> $$\frac{d}{t} = 60$$

=> $$d = 60t$$ ————–(i)

For second car, => $$\frac{d}{t – 2} = 108$$

Substituting value of $$d$$ from equation (i), we get :

=> $$60t = 108t – 216$$

=> $$108t – 60t = 48t = 216$$

=> $$t = \frac{216}{48} = 4.5$$ hrs

From equation (i), => $$d = 60 \times 4.5 = 270$$ km

=> Ans – (A)

**5) Answer (d)**

Let the distance between City A and City B = d km

Speed of first car = 30 km/hr and speed of second car = 45 km/hr

Let time taken by first car = t hrs and time taken by second car = $$(t – 2.5)$$ hrs

Using, speed = distance/time for first car :

=> $$\frac{d}{t} = 30$$

=> $$d = 30t$$ ————–(i)

For second car, => $$\frac{d}{t – 2.5} = 45$$

Substituting value of $$d$$ from equation (i), we get :

=> $$30t = 45t – 112.5$$

=> $$45t – 30t = 15t = 112.5$$

=> $$t = \frac{112.5}{15} = 7.5$$ hrs

From equation (i), => $$d = 30 \times 7.5 = 225$$ km

=> Ans – (D)

**6) Answer (d)**

The car covers 216 km in 3.2 hours

Speed of car (in km/hr) = $$\frac{216}{3.2} = 67.5$$ km/hr

=> Speed in m/s = $$67.5 \times \frac{5}{18}$$

= $$5 \times 3.75 = 18.75$$ m/s

$$\therefore$$ In 1 second, it travels 18.75 metres

=> Ans – (D)

**7) Answer (a)**

Time taken to build the wall = 70 hours

Time spent = 7 hours

=> Fraction of the wall yet to be built = $$\frac{(70 – 7)}{70} = \frac{63}{70}$$

= $$\frac{9}{10} = 0.9$$

=> Ans – (A)

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