Ratio and proportion was important topic for all competitive exams. The concepts to learn are less and the practice can improve your speed a lot, Mostly the questions are easily to solve and will be combined with other applications of ages, mixtures and proportions topics.

**Ratio and Proportion for SSC CHSL:**

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**Question 1:
**

By increasing the price of entry ticket to a fair in the ratio 9:13, the number of visitors to the fair has decreased in the ratio 7:4. In what ratio has the total collection increased or decreased?

a) increased in the ratio 52:63

b) increased in the ratio 36:91

c) decreased in the ratio 63:52

d) decreased in the ratio 91:36

**Question 2:
**

If Giridhar’s salary is 5/3 times of Hariraj’s and Shaunak’s is 2/3 times of Hariraj’s, what is the ratio of Giridhar’s salary to Shaunak’s.

a) 9:10

b) 10:9

c) 5:2

d) 2:5

**Question 3:**

In an army selection process, the ratio of selected to unselected was 3:1. If 60 less had applied and 30 less selected, the ratio of selected to unselected would have been 5:1. How many candidates had applied for the process?

a) 240

b) 480

c) 120

d) 720

**Question 4:**

The bus fare between two cities is increased in the ratio 11:18. What would be the increase in the fare, if the original fare is Rs 550?

a) Rs 350

b) Rs 900

c) Rs 180

d) Rs 360

**Question 5:**

The third proportional of two numbers 4 and 28 is _______.

a) 52

b) 56

c) 84

d) 196

**Question 6:**

The third proportional of two numbers 9 and 15 is

a) 21

b) 30

c) 25

d) 45

**Question 7:**

The bus fare between two cities is increased in the ratio 25:29. Find the increase in the fare, if the original fare is Rs. 625

a) Rs 725

b) Rs 145

c) Rs 290

d) Rs 100

**Question 8:
**

The third proportional of two numbers 24 and 36 is ?

a) 48

b) 54

c) 72

d) 108

**Solutions (1 to 8)**

1) Answer (c)

Let cost of original ticket = Rs 9 and and number of visitors = 70

=> Original revenue = 9 $$\times$$ 70 = Rs 630

After increase in cost of ticket

New cost of ticket = Rs 13 and number of visitors = 40

=> New Revenue = 13 $$\times$$ 40 = Rs 520

Since, new revenue is less than original revenue, thus total collection has decreased.

$$\therefore$$ Decrease in total collection ratio = $$\frac{630}{520}$$ = 63 : 52

=> Ans – (C)

**2) Answer (c)
**Let Hariraj’s salary = $$3x$$

=> Giridhar’s salary = $$\frac{5}{3} \times 3x = 5x$$

=> Shaunak’s salary = $$\frac{2}{3} \times 3x = 2x$$

$$\therefore$$ Ratio of Giridhar’s salary to Shaunak’s = $$\frac{5x}{2x}$$

= 5 : 2

=> Ans – (C)

3) Answer (a)

Let $$4x$$ candidates applied for the process.

Candidates selected = $$3x$$ and candidates not selected = $$x$$

If candidates applied = $$4x – 60$$

Candidates selected = $$3x – 30$$

=> Candidates not selected = $$(4x – 60) – (3x – 30) = x – 30$$

According to ques,

=> $$\frac{3x – 30}{x – 30} = \frac{5}{1}$$

=> $$3x – 30 = 5x – 150$$

=> $$2x = 150 – 30 = 120$$

=> $$x = \frac{120}{2} = 60$$

$$\therefore$$ Number of candidates who applied for the process = $$4 \times 60 = 240$$

=> Ans – (A)

** **

**4) Answer (a)**

Let original fare = Rs. $$11x$$

=> New fare = Rs. $$18x$$

Also, original fare = $$550 = 11x$$

=> $$x = \frac{550}{11} = 50$$

$$\therefore$$ Increase in fare = $$18x – 11x = 7x $$

= $$7 \times 50 = Rs. 350$$

**5) Answer (d)
**

Three numbers a,b,c are in proportion iff $$b^2 = ac$$

Here, a = 4 and b = 28

=> $$(28)^2 = 4 \times c$$

=> $$c = \frac{28 \times 28}{4} = 7 \times 28$$

=> $$c = 196$$

=> Ans – (D)

**6) Answer (c)
**

Three numbers a,b,c are in proportion iff $$b^2 = ac$$ where $$b$$ is the mean proportion and $$c$$ is the third proportion

The given numbers are 9 and 15

=> $$(15)^2 = 9 \times c$$

=> $$c = \frac{15 \times 15}{9}$$

=> $$c = 5 \times 5 = 25$$

=> Ans – (C)

**7) Answer (d)**

Let original fare = Rs. $$25x$$

=> New fare = Rs. $$29x$$

Also, original fare = $$625 = 25x$$

=> $$x = \frac{625}{25} = 25$$

$$\therefore$$ Increase in fare = $$29x – 25x = 4x $$

= $$4 \times 25 = Rs. 100$$

**8) Answer (b)**

Three numbers a,b,c are in proportion iff $$b^2 = ac$$

Here, a = 24 and b = 36

=> $$(36)^2 = 24 \times c$$

=> $$c = \frac{36 \times 36}{24} = 3 \times 18$$

=> $$c = 54$$

=> Ans – (B)

We hope this ratio and proportion questions for SSC CHSL and CGL are useful to you.

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