**Profit and Loss, Discount Questions for SSC-CPO Set-2 PDF**

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**Question 1:Â **Some fruits are bought at a rate of 11 for â‚¹100 and an equal number at a rate of 9 for â‚¹100. If all the fruits are sold at a rate of 10 for â‚¹100, then what is the gain or loss percent in the entire transaction?

a)Â Gain, 1%

b)Â Loss, 5%

c)Â Gain, 5%

d)Â Loss, 1%

**Question 2:Â **Ramesh purchases 75 articles for â‚¹ 10800 and sells them at a loss equal to the selling price of 5 articles. What will be the selling price of one article?

a)Â â‚¹156

b)Â â‚¹135

c)Â â‚¹144

d)Â â‚¹132

**Question 3:Â **After giving a discount of 25%, a shopkeeper earns 40% profit. Marked price is what percent more than the cost price?

a)Â 80%

b)Â 75%

c)Â 86.67%

d)Â 85%

**Question 4:Â **Marked price of an article is 60% more than its cost price. If the article is sold at a profit of 20%, then what will be the discount percentage?

a)Â 37.5%

b)Â 17.5%

c)Â 15%

d)Â 25%

**Question 5:Â **x buys a scooter for â‚¹ 40,000 and spends â‚¹ 5,000 on its repair. He sells it for â‚¹ 54,000. What is the gain percent?

a)Â 12.50%

b)Â 20%

c)Â 25%

d)Â 15%

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**Question 6:Â **An article was bought for â‚¹ 400 and a repairing charge of â‚¹ 50 was paid on it. It is sold at a profit of 20%,after a discount of 10% on its marked price. The marked price is:

a)Â â‚¹540

b)Â â‚¹640

c)Â â‚¹580

d)Â â‚¹600

**Question 7:Â **An article was sold for â‚¹4,000. Had a discount of 10% was being offered, the profit would have been 20%. The cost price of the article was:

a)Â â‚¹3,200

b)Â â‚¹3,310

c)Â â‚¹3,000

d)Â â‚¹3,600

**Question 8:Â **A discount of 20% in the price of rice enables X to buy 5 kg more rice for â‚¹100. What is the reduced price of rice per kg?

a)Â â‚¹3

b)Â â‚¹2

c)Â â‚¹1

d)Â â‚¹4

**Question 9:Â **The cost price of 27 articles is same as the selling price of 18 articles. Whatis the profit percent?

a)Â 40%

b)Â 50%

c)Â 30%

d)Â 25%

**Question 10:Â **If 15 apples cost as muchas 6 strawberries, 2 strawberries cost as much as 16 bananas, 6 bananas cost as much as 15 potatoes, then whatis the cost of 1 potato if an apple costs â‚¹ 20?

a)Â â‚¹25

b)Â â‚¹22.50

c)Â â‚¹2.50

d)Â â‚¹2.25

**Question 11:Â **If the selling price is tripled, the profit becomes 5 times. What is the profit percent?

a)Â 100%

b)Â 200%

c)Â 50%

d)Â 150%

**Question 12:Â **A cloth piece was purchased for â‚¹ 700. At what price should it be sold to get a profit of 12.5% after a tailoring charge of â‚¹ 20 was paid for?

a)Â â‚¹760

b)Â â‚¹810

c)Â â‚¹785

d)Â â‚¹840

**Question 13:Â **The list price of an article is â‚¹ 80. A customer pays â‚¹ 30 for it. He was given 2 successive discounts, one of them being 50%. What was the other discount?

a)Â 20%

b)Â 12.50%

c)Â 30%

d)Â 25%

**Question 14:Â **A trader sold an item at a loss of 20%. Had he sold it for â‚¹100 more, he would have gained a profit of 5%. What is the cost price of the item?

a)Â â‚¹ 250

b)Â â‚¹ 200

c)Â â‚¹ 25

d)Â â‚¹ 400

**Question 15:Â **A person bought an item and sold it at a loss of 5%. If he had bought it for 10% less and sold it for â‚¹ 170 more, he would have had a profit of 20%, Find the cost price of this item. (nearest toÂ â‚¹1)

a)Â â‚¹1440

b)Â â‚¹1308

c)Â â‚¹1300

d)Â â‚¹1500

**Answers & Solutions:**

**1)Â AnswerÂ (D)**

We know that CP is cost price

SP is selling price

In first condition

CP of 11 toffee=â‚¹10

CP of 1 fruits = â‚¹ (Â $\frac{10}{11}$ )

in second condition

CP of 9Â fruits= â‚¹ 10

CP of fruitsÂ = â‚¹ (Â $\frac{10}{9}$ )

therefore, CP of both fruits = â‚¹ $\frac{10}{11}$+â‚¹Â $\frac{10}{9}$

= â‚¹ $\frac{200}{99}$

so, cp of 1 = $\frac{200}{99}$ Ã·2

Cost price = â‚¹Â Â $\frac{100}{99}$

sp of 1Â fruits = â‚¹ 1(given)

loss=cost price – selling price

= $\frac{100}{99}$ – 1

Loss = â‚¹Â $\frac{1}{99}$

loss percentage = $\frac{loss}{cost price}$Ã—100

loss (%) =Â $\frac{1Ã·99}{100Ã·99}$Ã—100

loss percent=1% loss

=1 percent loss

**2)Â AnswerÂ (B)**

Given that the Cost Price of 75 articles = Rs.10800

Let the Selling Price of each article = Rs.x

Then, Selling Price of 75 articles = Rs.75x

Selling Price of 5 articles = Rs.5x

=> 10800 – 75x = 5x

=> 80x = 10800

=> x = 135

Therefore, Selling Price of each article = Rs.135

**3)Â AnswerÂ (C)**

Let the Marked Price be Rs.100x

Discount = 25% of Rs.100x = Rs.25x

Selling Price = Rs.100x – Rs.25x = Rs.75x

Cost Price = $75x\times\dfrac{100}{140} = \dfrac{Rs.375x}{7}$

Required percentage = $\dfrac{100x – \dfrac{375x}{7}}{\dfrac{375x}{7}}\times100 = \dfrac{325}{375}\times100 = 86.67$%

**4)Â AnswerÂ (D)**

Let the Cost Price be Rs.100x

Then, Marked Price = 160% of 100x = Rs.160x

Given, Profit = 20%

Selling Price = 120% of Rs.100x = Rs.120x

Discount percentage = $\dfrac{160x – 120x}{160x} \times 100 = \dfrac{40x}{160x}\times100 = 25$%

**5)Â AnswerÂ (B)**

Total Cost Price of the scooter = Rs.40000+Rs.5000 = Rs.45000

Selling Price = Rs.54000

Gain percent = $\dfrac{54000-45000}{45000}\times100 = \dfrac{9000}{45000}\times100 = 20$%

**6)Â AnswerÂ (D)**

Total Cost Price = Rs.400+Rs.50 = Rs.450

Selling Price = $Rs.450 \times \dfrac{120}{100} = Rs.540$

Discount = 10%

Then, Marked Price = $540 \times \dfrac{100}{90} = Rs.600$

**7)Â AnswerÂ (C)**

Selling Price of the article = Rs.4000

Let the marked price of the article be Rs.100x

100x = Rs.4000

x = Rs.40

Selling price after 10% discount = 90% of Rs.100x = Rs.90x

Profit = 20%

Then, Cost Price = $90x \times \dfrac{100}{120} = Rs.75x = Rs.75*40 = Rs.300$

**8)Â AnswerÂ (D)**

X can buy 5 kg more rice for Rs.100

Then, X can buy 1 kg more rice for Rs.20

Then, Reduced price = $Rs.20 \times \dfrac{20}{100} = Rs.4$

**9)Â AnswerÂ (B)**

27 CP = 18 SP

$\dfrac{SP}{CP} = \dfrac{27}{18} = \dfrac{3}{2}$

Subtracting 1 from both sides

=> $\dfrac{SP}{CP} – 1 = \dfrac{3}{2} – 1$

=> $\dfrac{SP-CP}{CP} = \dfrac{3-2}{2} = \dfrac{1}{2}$

Multiplying 100 on both sides

=> $\dfrac{SP-CP}{CP} \times 100 = \dfrac{1}{2}\times 100 = 50$%

**10)Â AnswerÂ (C)**

15A = 6S => A : S = 6 :Â 15

2S = 16B => S : B = 16 : 2

6B = 15P => B : P = 15 : 6

where A = Apples, S = Straw berries, B = Bananas and P = Potatoes

Multiplying A : S by 16 and S : B by 15,

A : S = 96 : 240 and S : B = 240 : 30

Hence, A : S : B = 96 : 240 : 30

Multiplying B : P by 2,

B : P = 30 : 12

Then, A : S : B : P = 96 : 240 : 30 : 12

Let the cost of Apples, Straw berries, Bananas and Potatoes be Rs.96x, Rs,240x, Rs.30x and Rs.12x respectively.

Given, Rs.96x = 20 => x = $\dfrac{20}{96} = \dfrac{5}{24}$

Therefore, Cost of 1 potato =Â 12x = $12\times \dfrac{5}{24} = Rs.2.5$

**11)Â AnswerÂ (A)**

Let the Cost Price be Rs.100 and Selling Price be Rs.x

Then, Profit = Rs.(x – 100)

New Selling Price = Rs.3x

Then, New profit = Rs,(3x-100)

Given, 3x-100 = 5(x-100) => 2x = 400 => x = 200

Hence, Selling Price = Rs.200

Profit percentage = $\dfrac{200-100}{100}\times100 = 100$%

**12)Â AnswerÂ (B)**

Total Effective Cost Price = Rs.700+Rs.20 = Rs.720

Required Profit = 12.5% = $\dfrac{1}{8}$

Therefore, Required Selling Price = $Rs.720 +Â \dfrac{1}{8} \times 720 = Rs.720+90 = Rs.810$

**13)Â AnswerÂ (D)**

Given, Marked Price = Rs.80

Selling Price = Rs.30

Discount = Rs.80-Rs.30 = Rs.50

One discount = 50%

50% of 80 = Rs.40

Let the other discount be x%

$40 \times \dfrac{100-x}{100} = 30$

=> 200-2x = 150 => 2x = 50 => x = 25

Therefore, The other discount = 25%

**14)Â AnswerÂ (D)**

Let the Cost Price be Rs.100x

Loss = 20%

Selling Price = 80% of 100x = Rs.80x

Profit = 5%

Selling Price = 105% of 100x = Rs.105x

Given, Rs.105x – Rs.80x = Rs.100

Rs.25x = Rs.100

=> x = 4

Therefore, Cost Price = Rs.100x = Rs.100*4 = Rs.400

**15)Â AnswerÂ (B)**

let CP=x

SP=0.95x

New CP=0.9*x

New SP=0.95x+170

profit=20%

0.95x+170=1.2(0.9x)

0.13x=170

x=1307.6

x=Rs 1308

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