Question 91

There are 3 numbers. The $$2^{nd}$$ number is 3 times the $$1^{st}$$. The $$3^{rd}$$ is twice the $$2^{nd}$$. If their average is 70, find the smallest of the 3 numbers.

Solution

Let the 1st number be x

Then 2nd number = 3x and 3rd number = 6x

Average = $$\frac{x+3x+6x}{3}$$

70=$$\frac{10x}{3}$$

10x=210

Smallest number = x = 21

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