Question 68

If $$a=5, b=4. c=8$$ then find the value of $$(a^3+b^3+c^3-3abc)/(ab+bc+ca-a^2-b^2-c^2)$$.

Solution

$$(a^3+b^3+c^3-3abc)/(ab+bc+ca-a^2-b^2-c^2)$$

Given

$$a=5, b=4. c=8$$

$$(5^3+4^3+8^3-3\times5\times4\times8)/(5\times4+4\times8+8\times5-5^2-4^2-8^2)$$

$$(125+64+512-480)/(20+32+40-25-16-64)$$

$$(221)/(-13)$$

$$-17$$

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