Find the fraction which is as much greater than $$\frac{4}{7}$$ as it is less than $$\frac{5}{6}$$:
Let the fraction be $$\frac{x}{y}$$
according to the qusetion,
$$\frac{x}{y}-\frac{4}{7}=\frac{5}{6}-\frac{x}{y}$$
$$\frac{x}{y}+\frac{x}{y}=\frac{5}{6}+\frac{4}{7}$$
$$\frac{2x}{y}=\frac{59}{42}$$
$$\frac{x}{y}=\frac{59}{84}$$
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