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Question 58
Perimeter of an isosceles triangle is 32 cm. The base is $$\frac{6}{5}$$times the equal side. What is the area?
Solution
let one side be x
then the equal sides be 2x
base is 6/5 times of x = $$ \frac{6}{5}x $$
perimeter = 32 ( given )
perimeter = 2x + $$ \frac{6}{5}x $$
32 = 2x + $$ \frac{6}{5}x $$
solving x = 10
now sides are 10, 10, 12( $$ \frac{6}{5} \times 10 $$ )
area = $$ \frac{1}{4} b \sqrt{P(P - 2b)} $$
    = $$ \frac{1}{4} 12 \sqrt{32(32 - 2 \times 12)} $$
    = $$ 48 cm^2 $$Â
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