Question 50
X and Y are parents of four married sons, one married daughter and one unmarried daughter living in a joint family. Two of the sons have two daughters and one son each. The other two have two sons and one daughter each. How many male members are there in the family?
Solution
- FATHER =1 male
- four married sons = 4 male
- two of the sons have one son each = 2 male
- the other two sons have two sons = 4 male
Total male = 1 + 4 + 2 + 4 = 11 male.
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