If the $$ a_{th} $$ part of 49 is 7 and $$ b_{th} $$ part of 63 is 9 and $$ c_{th} $$ part of 112 is 16. Then which of the following is true:

A

abc= $$ \frac {1}{7} $$

B

abc= $$ a^{3} $$

C

abc= $$ \frac {1}{49} $$

D

abc= $$ \frac {c}{a} $$