Question 34

Two squares differ in areas by 32 cm². If the difference in their sides is 4 cm, what are the sides of the two squares?

Solution

Let say, their sides are a and b.

So, $$a^2-b^2$$=32

and $$a-b$$=4.........(1)

So, $$(a+b)(a-b)$$=32.

or, (a+b)=8..........(2)

By solving (1) and (2) we get :

a=6 and b=2.

C is correct choice.

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