Question 34

Two squares differ in areas by 32 cm². If the difference in their sides is 4 cm, what are the sides of the two squares?

Solution

Let say, their sides are a and b.

So, $$a^2-b^2$$=32

and $$a-b$$=4.........(1)

So, $$(a+b)(a-b)$$=32.

or, (a+b)=8..........(2)

By solving (1) and (2) we get :

a=6 and b=2.

C is correct choice.

Create a FREE account and get:

Download RRB Study Material PDF
45+ RRB previous papers with solutions PDF
300+ Online RRB Tests for Free

Follow us on

Boost your Prep!

Download App