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SSC CHSL Quant Previous Repeatedly asked Questions With Video Explanations PDF

For Previous year Quant questions of SSC CHSL 2018 Tier I exam download PDF. Go through the video of Repeatedly asked Quant questions explanations.

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Question 1:Â The simple interest on a sum for 8 years is Rs 47500. The rate of interest for the first 5 years is 10% per annum and for the next 3 years is 15% per annum. What is the value (in Rs) of sum?

a)Â 50000

b)Â 60000

c)Â 45000

d)Â 62500

Question 2:Â Selling price of a chair is Rs 1386. If loss percentage is 23%, then what is the cost price (in Rs) of chair?

a)Â 1600

b)Â 1800

c)Â 1900

d)Â 1067

Question 3:Â Marked price of a computer is Rs 48000 and discount is 13%. What is additional discount (in percentage) should be offered to the customer to bring the price of computer to Rs 39672?

a)Â 10

b)Â 5

c)Â 8

d)Â 9

Question 4:Â Which of the following statement is/are true ?
I. $\sqrt{144}\times\sqrt{36}<\sqrt[3]{125}\times\sqrt{121}$
II.$\sqrt{324}+\sqrt{49}>\sqrt[3]{216}\times\sqrt{9}$

a)Â Only I

b)Â Only II

c)Â Neither I nor II

d)Â Both I and II

Question 5:Â Pipe X can fill a tank in 20 hours and Pipe Y can fill the tank in 35 hours. Both the pipes are opened on alternate hours. Pipe Y is opened first, then in how much time (in hours) the tank will be full?

a)Â 269/11

b)Â 280/11

c)Â 179/7

d)Â 172/7

SSC CHSL Study Material (FREE Tests)

Question 6:Â A train is moving at the speed of 54 km/hr. How many seconds it will take to cover a distance of 450 metres?

a)Â 60

b)Â 30

c)Â 45

d)Â 36

Instructions

The bar graph shows average marks scored in a 100 marks Science exam by students of 7 divisions of Standard X. Study the diagram and answer the following questions.

Average Science Marks

Division

Question 7:Â Which division scored the second lowest marks?

a)Â F

b)Â B

c)Â G

d)Â D

Question 8:Â What is the ratio of average marks scored by Division D to Division A?

a)Â 4 : 5

b)Â 5 : 4

c)Â 4 : 7

d)Â 7 : 4

Question 9:Â Marks of division F were lesser than that of Division C by _________

a)Â 35%

b)Â 47.25%

c)Â 45%

d)Â 43.75%

Question 10:Â If all students of Division A lost 5 marks each for indiscipline then their new average marks would decrease by how much?

a)Â 5%

b)Â 11.11%

c)Â 6.67%

d)Â 10%

Let the sum = Rs. $100x$

Rate of interest for first 5 years = 10% and for next 3 years = 15%

=> Simple interest = $\frac{P\times R\times T}{100}$

=> $(\frac{100x\times 10\times5}{100})+(\frac{100x\times15\times3}{100})=47500$

=> $50x+45x=47500$

=> $x=\frac{47500}{95}=500$

$\therefore$ Sum = $100\times500=Rs.$ $50,000$

=> Ans – (A)

Selling price = Rs. 1386

Loss % = 23%

=> Cost price = $\frac{1386}{(100-23)}\times100$

= $\frac{126}{7}\times100=Rs.$ $1800$

=> Ans – (B)

Marked price of computer = Rs. 48,000 and discount = 13%

=> Selling price = $48,000-(\frac{13}{100}\times48,000)$

= $48000-6240=Rs.$ $41,760$

Final selling price = Rs. 39,672

=> Additional discountÂ % = $\frac{(41760-39670)}{41760}\times100$

= $\frac{2090}{417.6}\approx5\%$

=> Ans – (B)

IÂ : $\sqrt{144}\times\sqrt{36}<\sqrt[3]{125}\times\sqrt{121}$

L.H.S. = $12\times6=72$

R.H.S. = $5\times11=55$

Thus, L.H.S.Â > R.H.S.

IIÂ : $\sqrt{324}+\sqrt{49}>\sqrt[3]{216}\times\sqrt{9}$

L.H.S. = $18+7=25$

R.H.S. = $6\times3=18$

Thus, L.H.S. > R.H.S., which is correct.

$\therefore$ Only II is correct.

=> Ans – (B)

Let capacity of tank = L.C.M. (20,35) = 140 litres

Pipe X can fill the tank in 20 hours, => X’s efficiency = $\frac{140}{20}=7$ l/hr

Similarly, Y’s efficiency = $\frac{140}{35}=4$ l/hr

Pipes Y and X are alternatively opened, => Tank filled in 2 hours = $4+7=11$ litres

Multiplying both sides by 12, we get => Tank filled in $24$ hours = $132$Â litres

Now, its Y’s turn to be opened, it will 4 more litres, => In $25$Â hours = $136$Â litres

Thus, the remaining tank is filled by pipe X in $\frac{4}{7}$ hours

=> Total time = $25+\frac{4}{7}=\frac{179}{7}$ hours

=> Ans – (C)

Speed of train = 54 km/hr = $(54\times\frac{5}{18})=15$ m/s

Let time taken to cover 450 m = $t$ seconds

Using, time = distance/speed

=> $t=\frac{450}{15}=30$ seconds

=> Ans – (B)

Marks when arranged in ascending order are : $45<50<60<65<75,75<80$

Corresponding division isÂ : $F,G,D,B,A,E,C$

Thus, G division scored second lowest marks.

=> Ans – (C)

Average marks scored by Division DÂ = 60

Average marks scored by Division A = 75

=> Required ratio = $\frac{60}{75}=4:5$

=> Ans – (A)

Marks scored by Division F = 45

Marks scored by Division C =Â 80

=> Required % = $\frac{(80-45)}{80}\times100$

= $\frac{35\times5}{4}=43.75\%$

=> Ans – (D)

=> Required % decrease = $\frac{(75-70)}{75}\times100$
= $\frac{100}{15}=6.67\%$