SSC CHSL Quant Previous Repeatedly asked Questions With Video Explanations PDF
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Question 1:Â The simple interest on a sum for 8 years is Rs 47500. The rate of interest for the first 5 years is 10% per annum and for the next 3 years is 15% per annum. What is the value (in Rs) of sum?
a)Â 50000
b)Â 60000
c)Â 45000
d)Â 62500
Question 2:Â Selling price of a chair is Rs 1386. If loss percentage is 23%, then what is the cost price (in Rs) of chair?
a)Â 1600
b)Â 1800
c)Â 1900
d)Â 1067
Question 3:Â Marked price of a computer is Rs 48000 and discount is 13%. What is additional discount (in percentage) should be offered to the customer to bring the price of computer to Rs 39672?
a)Â 10
b)Â 5
c)Â 8
d)Â 9
Question 4:Â Which of the following statement is/are true ?
I. $\sqrt{144}\times\sqrt{36}<\sqrt[3]{125}\times\sqrt{121}$
II.$\sqrt{324}+\sqrt{49}>\sqrt[3]{216}\times\sqrt{9}$
a)Â Only I
b)Â Only II
c)Â Neither I nor II
d)Â Both I and II
Question 5:Â Pipe X can fill a tank in 20 hours and Pipe Y can fill the tank in 35 hours. Both the pipes are opened on alternate hours. Pipe Y is opened first, then in how much time (in hours) the tank will be full?
a)Â 269/11
b)Â 280/11
c)Â 179/7
d)Â 172/7
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Question 6:Â A train is moving at the speed of 54 km/hr. How many seconds it will take to cover a distance of 450 metres?
a)Â 60
b)Â 30
c)Â 45
d)Â 36
Instructions
The bar graph shows average marks scored in a 100 marks Science exam by students of 7 divisions of Standard X. Study the diagram and answer the following questions.
Average Science Marks
Division
Question 7:Â Which division scored the second lowest marks?
a)Â F
b)Â B
c)Â G
d)Â D
Question 8:Â What is the ratio of average marks scored by Division D to Division A?
a)Â 4 : 5
b)Â 5 : 4
c)Â 4 : 7
d)Â 7 : 4
Question 9:Â Marks of division F were lesser than that of Division C by _________
a)Â 35%
b)Â 47.25%
c)Â 45%
d)Â 43.75%
Question 10:Â If all students of Division A lost 5 marks each for indiscipline then their new average marks would decrease by how much?
a)Â 5%
b)Â 11.11%
c)Â 6.67%
d)Â 10%
Answers & Solutions:
1) Answer (A)
Let the sum = Rs. $100x$
Rate of interest for first 5 years = 10% and for next 3 years = 15%
=> Simple interest = $\frac{P\times R\times T}{100}$
=> $(\frac{100x\times 10\times5}{100})+(\frac{100x\times15\times3}{100})=47500$
=> $50x+45x=47500$
=> $x=\frac{47500}{95}=500$
$\therefore$ Sum = $100\times500=Rs.$ $50,000$
=> Ans – (A)
2) Answer (B)
Selling price = Rs. 1386
Loss % = 23%
=> Cost price = $\frac{1386}{(100-23)}\times100$
= $\frac{126}{7}\times100=Rs.$ $1800$
=> Ans – (B)
3) Answer (B)
Marked price of computer = Rs. 48,000 and discount = 13%
=> Selling price = $48,000-(\frac{13}{100}\times48,000)$
= $48000-6240=Rs.$ $41,760$
Final selling price = Rs. 39,672
=> Additional discount % = $\frac{(41760-39670)}{41760}\times100$
= $\frac{2090}{417.6}\approx5\%$
=> Ans – (B)
4) Answer (B)
IÂ : $\sqrt{144}\times\sqrt{36}<\sqrt[3]{125}\times\sqrt{121}$
L.H.S. = $12\times6=72$
R.H.S. = $5\times11=55$
Thus, L.H.S. > R.H.S.
IIÂ : $\sqrt{324}+\sqrt{49}>\sqrt[3]{216}\times\sqrt{9}$
L.H.S. = $18+7=25$
R.H.S. = $6\times3=18$
Thus, L.H.S. > R.H.S., which is correct.
$\therefore$ Only II is correct.
=> Ans – (B)
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5) Answer (C)
Let capacity of tank = L.C.M. (20,35) = 140 litres
Pipe X can fill the tank in 20 hours, => X’s efficiency = $\frac{140}{20}=7$ l/hr
Similarly, Y’s efficiency = $\frac{140}{35}=4$ l/hr
Pipes Y and X are alternatively opened, => Tank filled in 2 hours = $4+7=11$ litres
Multiplying both sides by 12, we get => Tank filled in $24$ hours = $132$Â litres
Now, its Y’s turn to be opened, it will 4 more litres, => In $25$Â hours = $136$Â litres
Thus, the remaining tank is filled by pipe X in $\frac{4}{7}$ hours
=> Total time = $25+\frac{4}{7}=\frac{179}{7}$ hours
=> Ans – (C)
6) Answer (B)
Speed of train = 54 km/hr = $(54\times\frac{5}{18})=15$ m/s
Let time taken to cover 450 m = $t$ seconds
Using, time = distance/speed
=> $t=\frac{450}{15}=30$ seconds
=> Ans – (B)
7) Answer (C)
Marks when arranged in ascending order are : $45<50<60<65<75,75<80$
Corresponding division is : $F,G,D,B,A,E,C$
Thus, G division scored second lowest marks.
=> Ans – (C)
8) Answer (A)
Average marks scored by Division DÂ = 60
Average marks scored by Division A = 75
=> Required ratio = $\frac{60}{75}=4:5$
=> Ans – (A)
9) Answer (D)
Marks scored by Division F = 45
Marks scored by Division C =Â 80
=> Required % = $\frac{(80-45)}{80}\times100$
= $\frac{35\times5}{4}=43.75\%$
=> Ans – (D)
10) Answer (C)
Current average marks of all students of Division A = 75
If all students of Division A lost 5 marks each, then new average marks = 75-5 = 70
=> Required % decrease = $\frac{(75-70)}{75}\times100$
= $\frac{100}{15}=6.67\%$
=> Ans – (C)